Answer: a) 2r The movement of a body following a circular path is called a circular motion. After half-circle displacement = AB = OA + OB Given ∴ AB = r + r AB = 2r As a result, the displacement after completing a half-circle is 2r.
Dear Aspirant, For a circle with r radius, circumference will be 2*pi*r, and therefore the distance travelled = pi*r that is half the circumference. For the displacement part, the particle will travel along the radius from one end to the other = 2*r(diameter). Ratio(d/s) = pi*r/2*r = pi/2. HOPE THIS HELPS. THANK YOU.
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CBSE 9 - Physics Asked by rahulkolapkar53 | 18 Aug, 2021, 02:28: PM ANSWERED BY EXPERT Answer VerifiedHint: Displacement is the shortest distance between two points and distance will be the actual distance. Displacement can be negative or positive according to the direction. But distance is always a positive quantity. The distance will always be equal or more than that of the displacement.Complete step by step answer: Distance is the actual path covered by the body and it is a scalar quantity, whereas the displacement is the shortest distance between the initial and final point. Displacement has magnitude and direction. Distance can’t be negative or zero.If a particle moves in a circular path of radius R, half of the revolution implies the semi-circle.
Text Solution Solution : Circumference of the circular path <br> = `2pir = 2 xx (22)/(7) xx 7 = 44` cm. <br> When it covers half the circumference the particle moves from A to B along the path ACB . <br> Hence distance covered `= (44)/(2) = 22` cm. Displacement is the length of straight line AB i.e., the diameter of the circle. Hence displacement is `2 xx 7` = 14 cm from A to B `vec((AB))`. <br> (ii) On completion of the total circular path ACBA, the distance covered is equal to the circumference of the circle = 44 cm. <br> As the particle comes back to its initial position displacement is zero. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P1_U02_C01_SLV_001_S01.png" width="80%"> Text Solution `2r, 2pi r ``r l2, pi r ``2r, pi r ``r, pir ` Answer : C Solution : Distance travelled by particle in circular path = length of semicircular path `= 1/2 xx` circumferene `= 1/2 xx 2 pi r= pi r ` and magnitude of displacement = distance between the opposite point on smicircular path = 2 r. |