 Text Solution Solution : When momentum is increased by `50%` velocity increases by `50%`, i.e., velcoity becomes `3//2` times, K.E. Becomes `9//4` times, i.e., `(9)/(4)xx100=225%`. Hence, increase in K.E. `=225-100=125%` Given that, The kinetic energy of the body becomes four times its initial value. Let us consider m to be the mass of the body. Let v be the velocity of the body with which the body moves. Then, the kinetic energy of the body is given as: Kinetic energy = 1/2 mv2 The momentum of the body is given as, P = mv We know that kinetic energy = 1/2 mv2 = 1/2 P2/m Because P = mv P2 = 2m × kinetic energy P is proportional to the square root of kinetic energy. Since 2 and m are considered as constants. Therefore, we can say that kinetic energy increased by four times. Therefore, when the kinetic energy increases by four times, then the moment will increase by two times.
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What is the percentage increase in the momentum if the velocity of the object increases 4 times?
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