TO FIND: Smallest number that, when divided by 35, 56 and 91 leaves remainder of 7 in each case L.C.M OF 35, 56 and 91 `35= 5xx7` `56=2^2xx7` `91=13xx7` L.C.M of 35,56 and 91 = `2^2xx5xx7xx13` =3640 Hence 84 is the least number which exactly divides 28, 42 and 84 i.e. we will get a remainder of 0 in this case. But we need the smallest number that, when divided by 35, 56 and 91 leaves remainder of 7 in each case Therefore = 3640 +7 = 3640
Hence 3640 is smallest number that, when divided by 35, 56 and 91 leaves remainder of 7 in each case. |