When length of the cuboid is increased by 20% the breadth of the cuboid is increased by 40% and the height is decreases by 10% the volume of the cuboid is increased by?

Question

Published: Published Date - 11:48 PM, Mon - 11 July 22

Hyderabad: This article is in continuation to the last article focusing on the percentage topic.

Here are some practice questions along with solutions that will help you in your preparation for the State government recruitment jobs.

2. If each edge of a cube is increased by 40%, the percentage increase in its surface area is
a) 40% b) 60% c) 80% d) 96%

Ans: d Solution: 40% = 40/100 = 2/5 Surface area = 6a²

Edge –>; 5 : 7

Surface area –>; 25 : 49

24/25 × 100% = 96%

3. The percentage increase in the surface area of a cube when each side is doubled is?

a) 50% b) 150% c) 200% d) 300%

Ans: d Solution: 100% = 100/100 = 1 Surface area = 6a²

Edge –>; 1 : 2

Surface area –>; 1 : 4

3/1 × 100% = 300%

4. If each side of a cube is decreased by 20%, the percentage decrease in its surface area is?

a) 20% b) 25% c) 35% d) 36%
Ans: d

Solution: 20% = -200/100 = -1/5

Surface area = 6a²

Side –>; 5 : 4 Surface area –>; 25 : 16 -9/25 × 100% = -36%

5. If each side of a cube is increased by 10%, then the percentage increase in its volume is?

a) 33.1% b) 33.5% c) 30% d) 32.5%

Ans: a Solution: 10% = 10/100 = 1/10 Volume = (Side)³ Side –>; 10 : 11 Volume –>; 10³ : 11³

1000 : 1331

331/1000 × 100% = 33.1%

6. If each side of a cube is doubled, then the percentage increase in its volume is?

a) 100% b) 400% c) 700% d) 800%

Ans: c Solution: 100% = 100/100= 1/1 Volume = (Side)³ Side –>; 1 : 2 Volume –>; 1³ : 2³

1 : 8

7/1 × 100% = 700%

7. If each side of a cube is decreased by 20%, then the percentage decrease in its volume is?

a) 44% b) 44.5% c) 48.8% d) 48%
Ans: c

Solution: 20% = -20/100 = -1/5

Volume = (Side)³

Side –>; 5 : 4

Volume –>; 5³ : 4³

125 : 64 – 61/125 × 100% = – 48.8%

8. If the length, breadth and height of a cuboid increased by 10%, 20% and 30% respectively, then the volume of a cuboid is increased by?

a) 104% b) 114% c) 124% d) 134%

Ans: d
Solution: 10% = 10/20 = 1/2, 20% = 20/100 = 1/5, 30% = 30/100 = 3/10

Volume = length × breadth × height

Length –>; 2 : 3
Breadth –>; 5 : 6

Height –>; 10 : 13

Volume –>; 2 × 5 × 10 : 3 × 6 × 13

50 : 117

67/50 × 100% = 134%
9. If the length of a cuboid is increased by 10%, breadth is increased by 20%, and the height is decreased by 20%, then the volume of a cuboid is increased/ decreased by?

a) 5.6% increases b) 5.6% decreases c) 6.5% increases d) 6.5% decreases

Ans: a

Solution: 10% = 10/100 = 1/10, 20% = 20/100 = 1/5, 20% = -20/100 = -1/5

Volume = length × breadth × height

Length –>; 10 : 11

Breadth –>; 5 : 6

Height –>; 5 : 4

Volume –>; 10 × 5 × 5 : 11 × 6 × 4

125 : 132

7/125 × 100% = 5.6%

= 5.6% increases
10. In a cuboid, if the length is increased by 63.63% and the breadth is decreased by 41 2/3%, then by how much percentage should the height be changed so that the volume remains constant?

a) 4.5% b) 4.76% c) 5% d) 5.76%

Ans: b
Solution: 63.63% = 7/11, 41 2/3% = -5/12

Volume = length × breadth × height

Length –>; 11 : 18

Breadth –>; 12 : 7

Height –>; 18×7 : 11×12 (volume remains constant)

21 : 22

1/21 × 100% = 4.76%

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Hello Prasad !

Formula for Volume of cuboid is , (length × breadth × height) cubic units.

So , if length is increased by 20% which means new length is 1.2 time of old length , similarly , new breadth will become 1.1 time more and height will become 0.95 times of old height , as it decreased.

So now , new volume will become , 1.2 * length × 1.1*breadth × 0.95*height ,

1.254 * length × breadth × height ,

Which means it get increased by 25.4 %

Hope it helps !

Given:

The ratio of length, breadth and height of cuboid was 5 : 4 : 3

The length of cuboid is increased by 20%

Breadth is increased by 25%

And height is increased by 33.33%

The total surface area of cuboid is increased by 216 cm2

Calculation:

Let the ratio be x