Solution:
We use the basic formula of probability to solve the problem.
Number of outcomes on throwing a die is (1, 2, 3, 4, 5, 6) = 6
Number of prime numbers on dice are 1, 3 and 5 = 3
(i) Probability of getting a prime number = Number of prime numbers/total number of outcomes
= 3/6 = 1/2
(ii) Numbers lying between 2 and 6 are 3, 4, 5 = 3
Probability of getting a number lying between 2 and 6 = Number lying between 2 and 6/total number of outcomes
= 3/6 = 1/2
(iii) Total number of odd numbers are 1, 3 and 5 = 3
Probability of getting a odd number = Number of odd numbers/total number of outcomes
= 3/6 = 1/2
☛ Check: NCERT Solutions Class 10 Maths Chapter 15
Video Solution:
A die is thrown once. Find the probability of getting (i) a prime number; (ii) a number lying between 2 and 6; (iii) an odd number.
NCERT Solutions for Class 10 Maths Chapter 15 Exercise 15.1 Question 13
Summary:
If a die is thrown once, then the probability of getting (i) a prime number, (ii) a number lying between 2 and 6, and (iii) an odd number are 1/2, 1/2, and 1/2 respectively.
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A die is thrown once. The probability of getting an odd number greater than 3 is a 1/3 b 1/6 c 1/2 d 0
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iii A dice is thrown once. Find the probability of getting an odd number.
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A die is thrown once. The probability of getting an odd number greater than 3 is
Total number of outcomes = 6.Out of the given numbers, odd number greater than 3 is 5.
Numbers of favourable outcomes = `("Number of favourable outcomes")/"Number of all possible outcomes"`
`= 1/6`Thus, the probability of getting an odd number greater than 3 is `1/6`.
ence, the correct answer is option `1/6`.
Concept: Basic Ideas of Probability
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