When a body is thrown up vertically with initial velocity u then maximum height reached by the body?

A body is thrown vertically upwards with an initial velocity u. Write the expression for the maximum height attained by the body.

A body is thrown vertically upwards with an initial velocity u. Write the expression for the maximum height attained by the body.

v2 = u2 - 2gh

We - get ,

`h_max = u^2/(2g)`

Concept: Newton's Third Law of Motion

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Question 16 Exercise 3E

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Answer:

There will be retardation when a body is thrown vertically upwards having an initial velocity ‘u’ to reach a height ‘h’. The final velocity ‘v’ at the highest point is 0m/s We know from the equation of motion that, \begin{array}{l} v^{2}=u^{2}-2 g h \\ h_{\max }=\frac{u^{2}}{2 g} \end{array}

Video transcript

hello everyone welcome to later learning i'm guri your science tutor today's question is a body is thrown vertically upwards with an initial velocity u write an expression for the maximum height attained by the body so let's start our answer when a body is thrown vertically upwards when body is thrown vertically upwards then it experiences retardation and its initial velocity u to reach the height h the final velocity becomes we at highest point is so from the equation of motion that v square is equals to u square minus 2 gh will give you the value of h maximum that is the maximum height which is equals to u square by 2g this is the required expression for more such videos please subscribe leader learning and for any doubts drop a comment thank you

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