What will be the mass of ascorbic acid c6h806 which is dissolved in 75 g acetic acid to decrease its freezing point by 1.5 C KF 3.9 K kg mol 1?

Mass of acetic acid, w1 = 75 g

Molar mass of ascorbic acid (C6H8O6), M2 = 6 × 12 + 8 × 1 + 6 × 16

= 176 g mol−1

Lowering of melting point, ΔTf = 1.5 K

We know that:

`triangleT_f = (K_fxxw_2xx1000)/(M_2xxw_1)`

`=>w_2=(triangle_fxxM_2xxw_1)/(K_fxx1000)`

`= (1.5xx176xx75) /(3.9xx1000)`

= 5.08 g (approx)

Hence, 5.08 g of ascorbic acid is needed to be dissolved.