What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Text Solution

Answer : `epsilon_(ph)=(epsilon_0cos(alpha+theta//2))/(sin alphasin(theta//2)); 0.37 MeV`

Solution : The problem can be solved with the aid of the laws of conservation of energy and the momentum (Fig.) <br> `epsilon_(ph)+epsilon_0=epsilon._(ph)+sqrt(epsilon_0^2+p^2c^2)` <br> `(epsilon_(ph))/c=(epsilon._(ph))/(c)costheta+pcosalpha,0=(epsilon._(ph))/(c)sin theta-"p"sinalpha` <br> where `epsilon_(ph) and epsilon._(ph)` share photon energies prior to and after its collision with the electron, and `epsilon_0and p` are the rest energy and the momentum of the electron. The unknown quantities `epsilon._(ph) and p` can be eliminated from this system, and we obtain <br> `epsilon._(ph)=pcsinalpha//sin theta` <br> The gives a system of two equaations : <br> `epsilon._(ph)+epsilon_0=(pcsinalpha)/(sin theta)+sqrt(epsilon_0^2+p^2c^2),epsilon_(ph)-(pcsin(alpha+theta))/(sin theta)` <br> Eliminating the momentum p of the recoil electron from this system, we obtain <br> `epsilon_(ph)+epsilon_0=(epsilon_(ph)sinalpha)/(sin(alpha+theta))+sqrt(epsilon_0^2+(epsilon_(ph)^2sin^2theta)/(sin^2(alpha+theta)))` <br> After tedious but simple transformations, we obtain the desired expression for the energy of the photon prior to collision . <br> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/ARG_AAP_PIP_PHY_C45_E01_017_S01.png" width="80%">

Scattering of photons off charged particles

Compton scattering, discovered by Arthur Holly Compton, is the scattering of a high frequency photon after an interaction with a stationary charged particle, usually an electron. If it results in a decrease in energy (increase in wavelength) of the photon (which may be an X-ray or gamma ray photon), it is called the Compton effect. Part of the energy of the photon is transferred to the recoiling electron. Inverse Compton scattering occurs when a charged particle transfers part of its energy to a photon.

Introduction

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Fig. 1: Schematic diagram of Compton's experiment. Compton scattering occurs in the graphite target on the left. The slit passes X-ray photons scattered at a selected angle. The energy of a scattered photon is measured using Bragg scattering in the crystal on the right in conjunction with ionization chamber; the chamber could measure total energy deposited over time, not the energy of single scattered photons.

Compton scattering is an example of inelastic scattering[1] of light by a free charged particle, where the wavelength of the scattered light is different from that of the incident radiation. In Compton's original experiment (see Fig. 1), the energy of the X ray photon (≈17 keV) was very much larger than the binding energy of the atomic electron, so the electrons could be treated as being free after scattering. The amount by which the light's wavelength changes is called the Compton shift. Although nucleus Compton scattering exists,[2] Compton scattering usually refers to the interaction involving only the electrons of an atom. The Compton effect was observed by Arthur Holly Compton in 1923 at Washington University in St. Louis and further verified by his graduate student Y. H. Woo in the years following. Compton earned the 1927 Nobel Prize in Physics for the discovery.

The effect is significant because it demonstrates that light cannot be explained purely as a wave phenomenon.[3] Thomson scattering, the classical theory of an electromagnetic wave scattered by charged particles, cannot explain shifts in wavelength at low intensity: classically, light of sufficient intensity for the electric field to accelerate a charged particle to a relativistic speed will cause radiation-pressure recoil and an associated Doppler shift of the scattered light,[4] but the effect would become arbitrarily small at sufficiently low light intensities regardless of wavelength. Thus, if we are to explain low-intensity Compton scattering, light must behave as if it consists of particles. Or the assumption that the electron can be treated as free is invalid resulting in the effectively infinite electron mass equal to the nuclear mass (see e.g. the comment below on elastic scattering of X-rays being from that effect). Compton's experiment convinced physicists that light can be treated as a stream of particle-like objects (quanta called photons), whose energy is proportional to the light wave's frequency.

As shown in Fig. 2, the interaction between an electron and a photon results in the electron being given part of the energy (making it recoil), and a photon of the remaining energy being emitted in a different direction from the original, so that the overall momentum of the system is also conserved. If the scattered photon still has enough energy, the process may be repeated. In this scenario, the electron is treated as free or loosely bound. Experimental verification of momentum conservation in individual Compton scattering processes by Bothe and Geiger as well as by Compton and Simon has been important in disproving the BKS theory.

Compton scattering is one of four competing processes when photons interact with matter. At energies of a few eV to a few keV, corresponding to visible light through soft X-rays, a photon can be completely absorbed and its energy can eject an electron from its host atom, a process known as the photoelectric effect. High-energy photons of 1.022 MeV and above may bombard the nucleus and cause an electron and a positron to be formed, a process called pair production; even-higher-energy photons (beyond a threshold energy of at least 1.670 MeV, depending on the nuclei involved), can eject a nucleon or alpha particle from the nucleus in a process called photodisintegration. Compton scattering is the most important interaction in the intervening energy region, at photon energies greater than those typical of the photoelectric effect but less than the pair-production threshold.

Description of the phenomenon

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Fig. 2: A photon of wavelength λ {\displaystyle \lambda }
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
comes in from the left, collides with a target at rest, and a new photon of wavelength λ ′ {\displaystyle \lambda '}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
emerges at an angle θ {\displaystyle \theta }
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
. The target recoils, carrying away an angle-dependent amount of the incident energy.

By the early 20th century, research into the interaction of X-rays with matter was well under way. It was observed that when X-rays of a known wavelength interact with atoms, the X-rays are scattered through an angle θ {\displaystyle \theta } and emerge at a different wavelength related to θ {\displaystyle \theta } . Although classical electromagnetism predicted that the wavelength of scattered rays should be equal to the initial wavelength,[5] multiple experiments had found that the wavelength of the scattered rays was longer (corresponding to lower energy) than the initial wavelength.[5]

In 1923, Compton published a paper in the Physical Review that explained the X-ray shift by attributing particle-like momentum to light quanta (Einstein had proposed light quanta in 1905 in explaining the photo-electric effect, but Compton did not build on Einstein's work). The energy of light quanta depends only on the frequency of the light. In his paper, Compton derived the mathematical relationship between the shift in wavelength and the scattering angle of the X-rays by assuming that each scattered X-ray photon interacted with only one electron. His paper concludes by reporting on experiments which verified his derived relation:

λ ′ − λ = h m e c ( 1 − cos ⁡ θ ) , {\displaystyle \lambda '-\lambda ={\frac {h}{m_{e}c}}(1-\cos {\theta }),}

where

  • λ {\displaystyle \lambda } is the initial wavelength,
  • λ ′ {\displaystyle \lambda '} is the wavelength after scattering,
  • h {\displaystyle h}
    What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
    is the Planck constant,
  • m e {\displaystyle m_{e}}
    What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
    is the electron rest mass,
  • c {\displaystyle c}
    What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
    is the speed of light, and
  • θ {\displaystyle \theta } is the scattering angle.

The quantity h/mec is known as the Compton wavelength of the electron; it is equal to 2.43×10−12 m. The wavelength shift λ′ − λ is at least zero (for θ = 0°) and at most twice the Compton wavelength of the electron (for θ = 180°).

Compton found that some X-rays experienced no wavelength shift despite being scattered through large angles; in each of these cases the photon failed to eject an electron.[5] Thus the magnitude of the shift is related not to the Compton wavelength of the electron, but to the Compton wavelength of the entire atom, which can be upwards of 10000 times smaller. This is known as "coherent" scattering off the entire atom since the atom remains intact, gaining no internal excitation.

In Compton's original experiments the wavelength shift given above was the directly-measurable observable. In modern experiments it is conventional to measure the energies, not the wavelengths, of the scattered photons. For a given incident energy E γ = h c / λ {\displaystyle E_{\gamma }=hc/\lambda }

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
, the outgoing final-state photon energy, E γ ′ {\displaystyle E_{\gamma ^{\prime }}}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
, is given by

E γ ′ = E γ 1 + ( E γ / m e c 2 ) ( 1 − cos ⁡ θ ) . {\displaystyle E_{\gamma ^{\prime }}={\frac {E_{\gamma }}{1+(E_{\gamma }/m_{e}c^{2})(1-\cos \theta )}}.}

Derivation of the scattering formula

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Fig. 3: Energies of a photon at 500 keV and an electron after Compton scattering.

A photon γ with wavelength λ collides with an electron e in an atom, which is treated as being at rest. The collision causes the electron to recoil, and a new photon γ' with wavelength λ' emerges at angle θ from the photon's incoming path. Let e' denote the electron after the collision. Compton allowed for the possibility that the interaction would sometimes accelerate the electron to speeds sufficiently close to the velocity of light as to require the application of Einstein's special relativity theory to properly describe its energy and momentum.

At the conclusion of Compton's 1923 paper, he reported results of experiments confirming the predictions of his scattering formula, thus supporting the assumption that photons carry momentum as well as quantized energy. At the start of his derivation, he had postulated an expression for the momentum of a photon from equating Einstein's already established mass-energy relationship of E = m c 2 {\displaystyle E=mc^{2}}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
to the quantized photon energies of h f {\displaystyle hf}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
, which Einstein had separately postulated. If m c 2 = h f {\displaystyle mc^{2}=hf}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
, the equivalent photon mass must be h f / c 2 {\displaystyle hf/c^{2}}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
. The photon's momentum is then simply this effective mass times the photon's frame-invariant velocity c. For a photon, its momentum p = h f / c {\displaystyle p=hf/c}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
, and thus hf can be substituted for pc for all photon momentum terms which arise in course of the derivation below. The derivation which appears in Compton's paper is more terse, but follows the same logic in the same sequence as the following derivation.

The conservation of energy E {\displaystyle E}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
merely equates the sum of energies before and after scattering.

E γ + E e = E γ ′ + E e ′ . {\displaystyle E_{\gamma }+E_{e}=E_{\gamma '}+E_{e'}.}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Compton postulated that photons carry momentum;[5] thus from the conservation of momentum, the momenta of the particles should be similarly related by

p γ = p γ ′ + p e ′ , {\displaystyle \mathbf {p} _{\gamma }=\mathbf {p} _{\gamma '}+\mathbf {p} _{e'},}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

in which ( p e {\displaystyle {p_{e}}}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
) is omitted on the assumption it is effectively zero.

The photon energies are related to the frequencies by

E γ = h f {\displaystyle E_{\gamma }=hf}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
E γ ′ = h f ′ {\displaystyle E_{\gamma '}=hf'}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

where h is Planck's constant.

Before the scattering event, the electron is treated as sufficiently close to being at rest that its total energy consists entirely of the mass-energy equivalence of its (rest) mass m e {\displaystyle m_{e}} ,

E e = m e c 2 . {\displaystyle E_{e}=m_{e}c^{2}.}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

After scattering, the possibility that the electron might be accelerated to a significant fraction of the speed of light, requires that its total energy be represented using the relativistic energy–momentum relation

E e ′ = ( p e ′ c ) 2 + ( m e c 2 ) 2   . {\displaystyle E_{e'}={\sqrt {(p_{e'}c)^{2}+(m_{e}c^{2})^{2}}}~.}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Substituting these quantities into the expression for the conservation of energy gives

h f + m e c 2 = h f ′ + ( p e ′ c ) 2 + ( m e c 2 ) 2 . {\displaystyle hf+m_{e}c^{2}=hf'+{\sqrt {(p_{e'}c)^{2}+(m_{e}c^{2})^{2}}}.}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

This expression can be used to find the magnitude of the momentum of the scattered electron,

p e ′ 2 c 2 = ( h f − h f ′ + m e c 2 ) 2 − m e 2 c 4 . {\displaystyle p_{e'}^{\,2}c^{2}=(hf-hf'+m_{e}c^{2})^{2}-m_{e}^{2}c^{4}.}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

(1)

Note that this magnitude of the momentum gained by the electron (formerly zero) exceeds the energy/c lost by the photon, 1 c ( h f − h f ′ + m e c 2 ) 2 − m e 2 c 4 > h f − h f ′ c   . {\displaystyle {\frac {1}{c}}{\sqrt {(hf-hf'+m_{e}c^{2})^{2}-m_{e}^{2}c^{4}}}>{\frac {hf-hf'}{c}}~.}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Equation (1) relates the various energies associated with the collision. The electron's momentum change involves a relativistic change in the energy of the electron, so it is not simply related to the change in energy occurring in classical physics. The change of the magnitude of the momentum of the photon is not just related to the change of its energy; it also involves a change in direction.

Solving the conservation of momentum expression for the scattered electron's momentum gives

p e ′ = p γ − p γ ′ . {\displaystyle \mathbf {p} _{e'}=\mathbf {p} _{\gamma }-\mathbf {p} _{\gamma '}.}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Making use of the scalar product yields the square of its magnitude,

p e ′ 2 = p e ′ ⋅ p e ′ = ( p γ − p γ ′ ) ⋅ ( p γ − p γ ′ ) = p γ 2 + p γ ′ 2 − 2 p γ p γ ′ cos ⁡ θ . {\displaystyle {\begin{aligned}p_{e'}^{\,2}&=\mathbf {p} _{e'}\cdot \mathbf {p} _{e'}=(\mathbf {p} _{\gamma }-\mathbf {p} _{\gamma '})\cdot (\mathbf {p} _{\gamma }-\mathbf {p} _{\gamma '})\\&=p_{\gamma }^{\,2}+p_{\gamma '}^{\,2}-2p_{\gamma }\,p_{\gamma '}\cos \theta .\end{aligned}}}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

In anticipation of p γ c {\displaystyle p_{\gamma }c}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
being replaced with h f {\displaystyle hf} , multiply both sides by c 2 {\displaystyle c^{2}}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
,

p e ′ 2 c 2 = p γ 2 c 2 + p γ ′ 2 c 2 − 2 c 2 p γ p γ ′ cos ⁡ θ . {\displaystyle p_{e'}^{\,2}c^{2}=p_{\gamma }^{\,2}c^{2}+p_{\gamma '}^{\,2}c^{2}-2c^{2}p_{\gamma }\,p_{\gamma '}\cos \theta .}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

After replacing the photon momentum terms with h f / c {\displaystyle hf/c}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
, we get a second expression for the magnitude of the momentum of the scattered electron,

p e ′ 2 c 2 = ( h f ) 2 + ( h f ′ ) 2 − 2 ( h f ) ( h f ′ ) cos ⁡ θ   . {\displaystyle p_{e'}^{\,2}c^{2}=(hf)^{2}+(hf')^{2}-2(hf)(hf')\cos {\theta }~.}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

(2)

Equating the alternate expressions for this momentum gives

( h f − h f ′ + m e c 2 ) 2 − m e 2 c 4 = ( h f ) 2 + ( h f ′ ) 2 − 2 h 2 f f ′ cos ⁡ θ , {\displaystyle (hf-hf'+m_{e}c^{2})^{2}-m_{e}^{\,2}c^{4}=\left(hf\right)^{2}+\left(hf'\right)^{2}-2h^{2}ff'\cos {\theta },}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

which, after evaluating the square and canceling and rearranging terms, further yields

2 h f m e c 2 − 2 h f ′ m e c 2 = 2 h 2 f f ′ ( 1 − cos ⁡ θ ) . {\displaystyle 2hfm_{e}c^{2}-2hf'm_{e}c^{2}=2h^{2}ff'\left(1-\cos \theta \right).}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Dividing both sides by 2 h f f ′ m e c {\displaystyle 2hff'm_{e}c}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
yields

c f ′ − c f = h m e c ( 1 − cos ⁡ θ ) . {\displaystyle {\frac {c}{f'}}-{\frac {c}{f}}={\frac {h}{m_{e}c}}\left(1-\cos \theta \right).}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

Finally, since = f ' λ' = c,

λ ′ − λ = h m e c ( 1 − cos ⁡ θ )   . {\displaystyle \lambda '-\lambda ={\frac {h}{m_{e}c}}(1-\cos {\theta })~.}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

(3)

It can further be seen that the angle φ of the outgoing electron with the direction of the incoming photon is specified by

cot ⁡ φ = ( 1 + h f m e c 2 ) tan ⁡ ( θ / 2 )   . {\displaystyle \cot \varphi =\left(1+{\frac {hf}{m_{e}c^{2}}}\right)\tan(\theta /2)~.}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?

(4)

Applications

Compton scattering is of prime importance to radiobiology, as it is the most probable interaction of gamma rays and high energy X-rays with atoms in living beings and is applied in radiation therapy.[6] [7]

Compton scattering is an important effect in gamma spectroscopy which gives rise to the Compton edge, as it is possible for the gamma rays to scatter out of the detectors used. Compton suppression is used to detect stray scatter gamma rays to counteract this effect.

Magnetic Compton scattering

Magnetic Compton scattering is an extension of the previously mentioned technique which involves the magnetisation of a crystal sample hit with high energy, circularly polarised photons. By measuring the scattered photons' energy and reversing the magnetisation of the sample, two different Compton profiles are generated (one for spin up momenta and one for spin down momenta). Taking the difference between these two profiles gives the magnetic Compton profile (MCP), given by J mag ( p z ) {\displaystyle J_{\text{mag}}(\mathbf {p} _{z})}

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
- a one-dimensional projection of the electron spin density.

J mag ( p z ) = 1 μ ∬ − ∞ ∞ ( n ↑ ( p ) − n ↓ ( p ) ) d p x d p y {\displaystyle J_{\text{mag}}(\mathbf {p} _{z})={\frac {1}{\mu }}\iint _{-\infty }^{\infty }(n_{\uparrow }(\mathbf {p} )-n_{\downarrow }(\mathbf {p} ))d\mathbf {p} _{x}d\mathbf {p} _{y}}

where μ {\displaystyle \mu }
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
is the number of spin-unpaired electrons in the system, n ↑ ( p ) {\displaystyle n_{\uparrow }(\mathbf {p} )}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
and n ↓ ( p ) {\displaystyle n_{\downarrow }(\mathbf {p} )}
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
are the three-dimensional electron momentum distributions for the majority spin and minority spin electrons respectively.

Since this scattering process is incoherent (there is no phase relationship between the scattered photons), the MCP is representative of the bulk properties of the sample and is a probe of the ground state. This means that the MCP is ideal for comparison with theoretical techniques such as density functional theory. The area under the MCP is directly proportional to the spin moment of the system and so, when combined with total moment measurements methods (such as SQUID magnetometry), can be used to isolate both the spin and orbital contributions to the total moment of a system. The shape of the MCP also yields insight into the origin of the magnetism in the system.[8]

Inverse Compton scattering

Inverse Compton scattering is important in astrophysics. In X-ray astronomy, the accretion disk surrounding a black hole is presumed to produce a thermal spectrum. The lower energy photons produced from this spectrum are scattered to higher energies by relativistic electrons in the surrounding corona. This is surmised to cause the power law component in the X-ray spectra (0.2–10 keV) of accreting black holes.[9]

The effect is also observed when photons from the cosmic microwave background (CMB) move through the hot gas surrounding a galaxy cluster. The CMB photons are scattered to higher energies by the electrons in this gas, resulting in the Sunyaev–Zel'dovich effect. Observations of the Sunyaev–Zel'dovich effect provide a nearly redshift-independent means of detecting galaxy clusters.

Some synchrotron radiation facilities scatter laser light off the stored electron beam. This Compton backscattering produces high energy photons in the MeV to GeV range[10][11] subsequently used for nuclear physics experiments.

Non-linear inverse Compton scattering

Non-linear inverse Compton scattering (NICS) is the scattering of multiple low-energy photons, given by an intense electromagnetic field, in a high-energy photon (X-ray or gamma ray) during the interaction with a charged particle, such as an electron.[12] It is also called non-linear Compton scattering and multiphoton Compton scattering. It is the non-linear version of inverse Compton scattering in which the conditions for multiphoton absorption by the charged particle are reached due to a very intense electromagnetic field, for example the one produced by a laser.[13]

Non-linear inverse Compton scattering is an interesting phenomenon for all applications requiring high-energy photons since NICS is capable of producing photons with energy comparable to the charged particle rest energy and higher.[14] As a consequence NICS photons can be used to trigger other phenomena such as pair production, Compton scattering, nuclear reactions, and can be used to probe non-linear quantum effects and non-linear QED.[12]

See also

  • Compton Gamma Ray Observatory
  • Klein–Nishina formula
  • Pair production
  • Peter Debye
  • Photoelectric effect
  • Radiation pressure
  • Resonant inelastic X-ray scattering
  • Thomson scattering
  • Timeline of cosmic microwave background astronomy
  • Non-linear inverse Compton scattering

References

  1. ^ Elastic or inelastic scattering? The incident photon loses energy in the lab frame, which centuries of practice had identified with inelastic scattering—even though, in the c.m. frame, the respective masses remaining the same, no new species are created and kinetic energy is conserved, the mark of an elastic collision. As a result, HEP and nuclear physicists prefer to emphasize elasticity, while atomic and molecular physicists use "inelastic".
  2. ^ P. Christillin (1986). "Nuclear Compton scattering". J. Phys. G: Nucl. Phys. 12 (9): 837–851. Bibcode:1986JPhG...12..837C. doi:10.1088/0305-4616/12/9/008.
  3. ^ Griffiths, David (1987). Introduction to Elementary Particles. Wiley. pp. 15, 91. ISBN 0-471-60386-4.
  4. ^ C. Moore (1995). "Observation of the Transition from Thomson to Compton Scattering in Optical Multiphoton Interactions with Electrons" (PDF).
  5. ^ a b c d Taylor, J.R.; Zafiratos, C.D.; Dubson, M.A. (2004). Modern Physics for Scientists and Engineers (2nd ed.). Prentice Hall. pp. 136–9. ISBN 0-13-805715-X.
  6. ^ Camphausen KA, Lawrence RC. "Principles of Radiation Therapy" Archived 2009-05-15 at the Wayback Machine in Pazdur R, Wagman LD, Camphausen KA, Hoskins WJ (Eds) Cancer Management: A Multidisciplinary Approach Archived 2013-10-04 at the Wayback Machine. 11 ed. 2008.
  7. ^ Ridwan, S. M., El-Tayyeb, F., Hainfeld, J. F., & Smilowitz, H. M. (2020). Distributions of intravenous injected iodine nanoparticles in orthotopic U87 human glioma xenografts over time and tumor therapy. Nanomedicine, 15(24), 2369–2383. https://doi.org/10.2217/nnm-2020-0178
  8. ^ Malcolm Cooper (14 October 2004). X-Ray Compton Scattering. OUP Oxford. ISBN 978-0-19-850168-8. Retrieved 4 March 2013.
  9. ^ Dr. Tortosa, Alessia. "Comptonization mechanisms in hot coronae in AGN. The NuSTAR view" (PDF). DIPARTIMENTO DI MATEMATICA E FISICA.
  10. ^ "GRAAL home page". Lnf.infn.it. Retrieved 2011-11-08.
  11. ^ "Duke University TUNL HIGS Facility". Retrieved 2021-01-31.
  12. ^ a b Di Piazza, A.; Müller, C.; Hatsagortsyan, K. Z.; Keitel, C. H. (2012-08-16). "Extremely high-intensity laser interactions with fundamental quantum systems". Reviews of Modern Physics. 84 (3): 1177–1228. arXiv:1111.3886. Bibcode:2012RvMP...84.1177D. doi:10.1103/RevModPhys.84.1177. ISSN 0034-6861. S2CID 118536606.
  13. ^ Meyerhofer, D.D. (1997). "High-intensity-laser-electron scattering". IEEE Journal of Quantum Electronics. 33 (11): 1935–1941. Bibcode:1997IJQE...33.1935M. doi:10.1109/3.641308.
  14. ^ Ritus, V. I. (1985). "Quantum effects of the interaction of elementary particles with an intense electromagnetic field". Journal of Soviet Laser Research. 6 (5): 497–617. doi:10.1007/BF01120220. ISSN 0270-2010. S2CID 121183948.

Further reading

  • S. Chen; H. Avakian; V. Burkert; L. Vandenaweele; P. Eugenio; the CLAS collaboration; Ambrozewicz; Anghinolfi; Asryan; Bagdasaryan; Baillie; Ball; Baltzell; Barrow; Batourine; Battaglieri; Beard; Bedlinskiy; Bektasoglu; Bellis; Benmouna; Berman; Biselli; Bonner; Bouchigny; Boiarinov; Bosted; Bradford; Branford; et al. (2006). "Measurement of Deeply Virtual Compton Scattering with a Polarized Proton Target". Physical Review Letters. 97 (7): 072002. arXiv:hep-ex/0605012. Bibcode:2006PhRvL..97g2002C. doi:10.1103/PhysRevLett.97.072002. PMID 17026221. S2CID 15326395.
  • Compton, Arthur H. (May 1923). "A Quantum Theory of the Scattering of X-Rays by Light Elements". Physical Review. 21 (5): 483–502. Bibcode:1923PhRv...21..483C. doi:10.1103/PhysRev.21.483. (the original 1923 paper on the APS website)
  • Stuewer, Roger H. (1975), The Compton Effect: Turning Point in Physics (New York: Science History Publications)
  • Compton Scattering – Georgia State University
  • Compton Scattering Data – Georgia State University
  • Derivation of Compton shift equation
  • Compton Scattering – Animation made by BIGS

What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
 Physics
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
 Astronomy
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
 Stars
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
 Spaceflight
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
 Outer space
What is the scattering angle theta in the Compton effect if the photon is backscattered from a rest electron?
 Solar System

Retrieved from "https://en.wikipedia.org/w/index.php?title=Compton_scattering&oldid=1109209512"