Kendall R. What is the percent by volume of isopropyl alcohol in a solution that contains 25 mL of isopropyl alcohol in 2.2 L of water?
1 Expert Answer
The question is a little vague. Is the isopropyl alcohol added to 2.2 liters of water, or is the FINAL volume of solution 2.2 liters? I'll assume the latter since we don't know if the volumes would be additive. Percent by volume means mls of solute per 100 mls of solution mls of solute = 25 ml isopropyl alcohol mls of solution = 2.2 L x 1000 ml/L = 2200 ml Percent by volume = 25 ml/2200 ml x 100 = 1.1 percent by volume
Colegio Decroly Americano
10th and 11th Grade Chemistry
Group Assessment Chapter #14 Solution Concentration
Names: Diego Diaz, Diego Henkle, Diego Gudiel, Rodrigo Medrano
Section 2 Solution Concentration: Practice Problems
9. What is the percent by mass of NaHCO
3
in a solution containing 20.0 g NaHCO
3
dissolved in 600.0 mL
H
2
O?
SOLUTION:
600.0 mL H
2
O x 1.0 g/mL = 600.0 g H
2
O
20 g NaHCO
3
/ 600 g H
2
O + 20g NaHCO
3
x 100 = 3%
10. You have 1500.0 g of a bleach solution. The percent by mass of the solute sodium hypochlorite, NaOCl, is
3.62%.How many grams of NaOCl are in the solution?
SOLUTION:
3.62% = 100 x mass NaOCl / 1500.0 g
Mass NaOCl = 54.3 g
11. In question 10, how many grams of solvent are in the solution?
SOLUTION:
1500.0 g - 54.3 g = 1445.7 solvent
12. Challenge The percent by mass of calcium chloride in a solution is found to be 2.65%. If 50.0 grams
of calcium chloride is used, what is the mass of the solution?
SOLUTION:
Mass of Solution= 1886.79 g
2.65% = 100 x 50 g CaCl2 / 1886.79 g
13. What is the percent by volume of ethanol in a solution that contains 35 mL of ethanol dissolved in 155 mL
of water?
SOLUTION:
35 mL/ 155 mL+ 35 mL x 100 = 18%
Answer = 18%
14. What is the percent by volume of isopropyl alcohol in a solution that contains 24 mL of isopropyl
alcohol in 1.1 L of water?
SOLUTION:
24 mL / 24 ml + 1100 mL x 100 = 2.1%
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15. Challenge If 18 mL of methanol are used to make an aqueous solution that is 15% methanol by volume,
how many milliliters of solution are produced?
SOLUTION:
15% = 18 mL / x mL solution x 100
x = 120
16. What is the molarity of an aqueous solution containing 40.0 g of glucose (C
6
H
12
O
6
) in 1.5 L of solution?
SOLUTION:
mol C
6
H
12
O
6
= 40.0 g x 1 ml / 180.16 g = 0.222 mol
molarity = mol C
6
H
12
O
6
/ 1.5 L solution = 0.222 mol / 1.5 L = 0.15 M
17. Calculate the molarity of 1.60 L of a solution containing 1.55 g of dissolved KBr.
SOLUTION:
mol KBr = 1.55 g x 1 mol / 119 g = 0.0130 mol KBr
molarity = mol KBr / 1.60 L solution = 0.0130 mol / 1.60 L = 8.13 x 10
-3
M
18. What is the molarity of a bleach solution containing 9.5 g of NaOCl per liter of bleach?
SOLUTION:
mol NaOCL = 9.5g x 1 mol / 74.44 g = 0.13 mol
molarity = mol NaOCl / 1.00 L solution = 0.128 mol / 1.00 L = 0.13 M
19. Challenge How much calcium hydroxide (Ca(OH)
2
), in grams, is needed to produce 1.5 L of a 0.25M
solution?
SOLUTION:
0.25 M = x mol Ca(OH)
2
/ 1.5 L solution
x = 0.38 mol Ca(OH)
2
0.38 mol Ca(OH)
2
x 74.08 g / mol = 28 g Ca(OH)
2
20. How many grams of CaCl
2
would be dissolved in 1.0 L of a 0.10M solution of CaCl
2
?
SOLUTION:
mol CaCl
2
= (0.10M)(1.0 L) = (0.10 mol / k) (1.0 K) = 0.10 mol CaCl
2
mass CaCl
2
= 0.10 mol CaCl
2
x 110.98 g / 1 mol
mass of CaCl
2
= 11g
21. How many grams of CaCl
2
should be dissolved in 500.0 mL of water to make a 0.20M solution of CaCl2?
SOLUTION:
500ml x 1L / 1000 ml x 0.20 M = 0,10 mol 0.10 mol CaCl
2
= 0.10 mol CaCl
2
x 110.98g / 1mol
mass of CaCl
2
= 11g
22. How many grams of NaOH are in 250 mL of a 3.0M NaOH solution?
SOLUTION:
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Colegio Decroly Americano
10th and 11th Grade Chemistry
Group Assessment Chapter #14 Solution Concentration
Names: Diego Diaz, Diego Henkle, Diego Gudiel, Rodrigo Medrano
Section 2 Solution Concentration: Practice Problems
9. What is the percent by mass of NaHCO3 in a solution containing 20.0 g NaHCO3 dissolved in 600.0 mL
H2O?
SOLUTION:
600.0 mL H2O x 1.0 g/mL = 600.0 g H2O
20 g NaHCO3 / 600 g H2O + 20g NaHCO3 x 100 = 3%
10. You have 1500.0 g of a bleach solution. The percent by mass of the solute sodium hypochlorite, NaOCl, is
3.62%.How many grams of NaOCl are in the solution?
SOLUTION:
3.62% = 100 x mass NaOCl / 1500.0 g
Mass NaOCl = 54.3 g
11. In question 10, how many grams of solvent are in the solution?
SOLUTION:
1500.0 g - 54.3 g = 1445.7 solvent
12. Challenge The percent by mass of calcium chloride in a solution is found to be 2.65%. If 50.0 grams
of calcium chloride is used, what is the mass of the solution?
SOLUTION:
Mass of Solution= 1886.79 g
2.65% = 100 x 50 g CaCl2 / 1886.79 g
13. What is the percent by volume of ethanol in a solution that contains 35 mL of ethanol dissolved in 155 mL
of water?
SOLUTION:
35 mL/ 155 mL+ 35 mL x 100 = 18%
Answer = 18%
14. What is the percent by volume of isopropyl alcohol in a solution that contains 24 mL of isopropyl
alcohol in 1.1 L of water?
SOLUTION:
24 mL / 24 ml + 1100 mL x 100 = 2.1%
15. Challenge If 18 mL of methanol are used to make an aqueous solution that is 15% methanol by volume,
how many milliliters of solution ...
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