The height of a tower is 10 m. What is the length of its shadow when Sun's altitude is 45°? Let BC be the length of shadow is x m Given that: Height of tower is 10 meters and altitude of sun is 45° Here we have to find length of shadow. So we use trigonometric ratios. In a triangle ABC, `⇒ tan = (AB)/(BC)` `⇒ tan 45°=(AB)/(AC)` `⇒1=10/x` `⇒x=10` Hence the length of shadow is 10 m. Concept: Heights and Distances Is there an error in this question or solution? Page 2If the ratio of the height of a tower and the length of its shadow is `sqrt3:1`, what is the angle of elevation of the Sun? Let C be the angle of elevation of sun is θ. Given that: Height of tower is `sqrt3` meters and length of shadow is 1. Here we have to find angle of elevation of sun. In a triangle ABC, `⇒ tanθ =(AB)/(BC)` `⇒ tan θ=sqrt3/1` ` [∵ tan 60°=sqrt3]` `⇒ tan θ=sqrt3` `⇒ θ=60 °` Hence the angle of elevation of sun is 60°. Concept: Heights and Distances Is there an error in this question or solution?
A statue, 1.6 m tall, stands on the top of a pedestal. From a point on the ground, the angle of elevation of the top of the statue is 60° and from the same point the angle of elevation of the top of the pedestal is 45°. Find the height of the pedestal.
Let height of the pedestal BD be h metres, and angle of elevation of C and D at a point A on the ground be 60° and 45° respectively.It is also given that the height of the statue CD be 1.6 mi.e., ∠CAB = 60°,∠DAB = 45° and CD = 1.6mIn right triangle ABD, we have In right triangle ABC, we have Comparing (i) and (ii), we get Hence, the height of pedestal
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