(i) Given Principal = Rs 2000, Rate of Interest = 5% per annum and Time = 5 years.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (2000 × 5 × 5)/100
= Rs 500
(ii) Given Principal = Rs 500, Rate of Interest = 12.5% per annum and Time = 4years.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (500 × 4 × 12.5)/100
= Rs 250
(iii) Given Principal = Rs 4500, Rate of Interest = 4% per annum andTime = 6 months = ½
years
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (4500 × ½ × 12.5)/100
SI = (4500 × 1 × 12.5)/100 × 2
= Rs 90
(iv) Given Principal = Rs 12000, Rate of Interest = 18% per annumand Time = 4 months =
(4/12) = (1/3) years
We know that simple interest = (P × T × R)/100
On substituting these values in above equation weget
SI = (12000 × (1/3) × 18)/100
SI = (12000 × 1 × 18)/100 × 3
= Rs 720
(v) Given Principal = Rs 1000, Rate of Interest = 10% per annumand
Time = 73 days = (73/365) days
We know that simple interest = (P × T × R)/100
On substituting these values in above equation weget
SI = (1000 × (73/365) × 10)/100
SI = (1000 × 73 × 10)/100 ×365
= Rs 20
What is the difference between the simple inter on a principal of Rs. 500 being calculated at 5
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