What is least 4 digit number which when divided by 3 4 5 and 6 leaves remainder of 2 in each case?

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Related What is the least four-digit number when divided by 3, 4, 5 and 6 leaves a remainder 2 in each case?a)1012b)1022c)1122d)1222Correct answer is option 'B'. Can you explain this answer?

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The lowest 4-digit number is 1000.

LCM of 3, 4, and 5 is 60.

Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4, and 5 is 1000 + (60 - 40) = 1020.

Now, add the remainder 2 that's required. Thus, the answer is 1022.

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15

Q:

Answer:   D) 1022

Explanation:

Lowest 4-digit number is 1000.LCM of 3, 4 and 5 is 60.Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.

Now, add the remainder 2 that's required. Thus, the answer is 1022.