The perimeter of a rectangle is 130 M if the breadth of the rectangle is 30 M find its area

Given: The perimeter of a rectangle is $130\ cm$. The breadth of the rectangle is $30\ cm$.

To do: To find the length and the area of the rectangle.

Solution: As given, the perimeter of the rectangle $P=130\ cm$

The breadth of the rectangle $b=30\ cm$

Let "$l$" be the length of the rectangle.

 We know that, $P=2(l+b)$

$\Rightarrow 130\ cm=2(l+30\ cm)$

$\Rightarrow 130\ cm=2l+60\ cm$

$\Rightarrow 2l=130-60$

$\Rightarrow 2l=70$

$\Rightarrow l=\frac{70}{2}$

$\Rightarrow l=35\ cm$

So, the area of the rectangle $A=l\times b$

$=35\ cm\times 30\ cm$

$=1050\ cm^2$

Therefore, the length of the rectangle is $35\ cm$, and the area of the rectangle is $1050\ cm^2$.

Solution:

Breadth of the rectangle = 30 cm

Perimeter of a rectangle = 130 cm

Perimeter of rectangle = 2 × [Length(l) + Breadth(b)]

130 cm = 2 × (l + 30 cm)

130 cm = 2l + 60 cm 

2l = 130 cm - 60 cm

2l = 70 cm

l = 70/2 cm

l = 35 cm

Area of Rectangle = Length × Breadth

= (35 × 30) cm2 

= 1050 cm2

☛ Check: NCERT Solutions Class 7 Maths Chapter 11

Video Solution:

Class 7 Maths NCERT Solutions Chapter 11 Exercise 11.1 Question 7

Summary:

The perimeter of a rectangle is 130 cm. If the breadth of the rectangle is 30 cm, its length is 35 cm. Also, the area of the rectangle is 1050 cm2.

☛ Related Questions:

Math worksheets and
visual curriculum