Six couples want to have their picture taken in how many ways can they arrange themselves in a row

Solution:

Given, there are 4 married couples

Total number of people = 8

we have to find how many ways can 4 married couples be seated in a row

a) if there are no restrictions on seating arrangement

The number of possible ways = n!

Here, n! = 8!

= 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1

= 40320 ways.

Therefore, there are 40320 ways that the people can be seated when there is no restriction on the seating arrangement.

b) if persons A and B must sit next to each other

The possible ways = 7! × 2!

= (7 × 6 × 5 × 4 × 3 × 2 × 1) × (2 × 1)

= 5040 × 2

= 10080

Therefore, if persons A and B must sit next to each other there are 10080 ways of seating arrangement.

c) if there are 4 men and 4 women and no 2 men or 2 women can sit next to each other

This implies the restriction of having persons of opposite sex next to each other.

We can have any one of the 8 persons in the first position.

So, both man and woman can be arranged without having same next to

each other = 8 × 4 × 3 × 3 × 2 × 2 × 1 × 1

= 1152 ways

Therefore, if there are 4 men and 4 women and no 2 men or 2 women can sit next to each other, there are 1152 ways of seating arrangement.

d) if there are 5 men and they must sit next to one another

There are 5 men and 3 women. 5 men sit next to one another.

The possible number of ways = 5! × 4!

= (5 × 4 × 3 × 2 × 1) × (4 × 3 × 2 × 1)

= 120 × 24

= 2880 ways

Therefore, if there are 5 men and they must sit next to one another, there are 2880 ways of seating arrangement.

e) if there are 4 married couples and each couple must sit together

4 pairs of couples can be arranged in 4!

Each couple can be arranged in 2! Ways.

The possible number of ways = 2! × 2! × 2! × 2!

= (2× 1) × (2 × 1) × (2 × 1) × (2 × 1) × (4 × 3 × 2 × 1)

= 2 × 2 × 2 × 2 × 24

= 16 × 24

= 384 ways

Therefore, if there are 4 married couples sitting together, there are 384 ways of seating arrangement.

In how many ways can 4 married couples (total of 8 people) be seated in a row if: (a) there are no restrictions on the seating arrangement? (b) persons A and B must sit next to each other?(c) there are 4 men and 4 women and no 2 men or 2 women can sit next to each other? (d) there are 5 men and they must sit next to one another? (e) there are 4 married couples and each couple must sit together?

Summary:

The possible number of ways can 4 married couples (total of 8 people) be seated in a row if:

(a) there are no restrictions on the seating arrangement is 40320 ways

(b) persons A and B must sit next to each other is 10080 ways

(c) There are 4 men and 4 women and no 2 men or 2 women can sit next to each other in 1152 ways.

(d) there are 5 men and they must sit next to one another is 2880 ways

(e) there are 4 married couples and each couple must sit together in 384 ways.

Six couples want to have their picture taken in how many ways can they arrange themselves in a row

Six couples want to have their picture taken in how many ways can they arrange themselves in a row
Six couples want to have their picture taken in how many ways can they arrange themselves in a row

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PHOTOGRAPHY A photographer is taking a picture of a bride and groom together with 6 attendants. How many ways can he arrange the 8 people in a row if the bride and groom stand in the middle?

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(a) Considering five couples as five special objects, we have 5! = 5*4*3*2*1 = 120 permutations of these objects. Next, we have 2 possible permutations (A,B) --> (B,A) inside each of 5 pairs. These permutations are independent --- so, there are

Six couples want to have their picture taken in how many ways can they arrange themselves in a row
= 32*120 = 3840 permutations of 5 couples, satisfying the imposed conditions. (b) If no restrictions are imposed, then there are 10! = 10*9*8*7*6*5*4*3*2*1 = 3628800 possible permutations of 10 persons. Solved. ---------------- On Permutations,  see introductory lessons

    - Introduction to Permutations


    - PROOF of the formula on the number of Permutations
    - Simple and simplest problems on permutations
    - Special type permutations problems
    - Problems on Permutations with restrictions
    - OVERVIEW of lessons on Permutations and Combinations in this site. Also,  you have this free of charge online textbook in ALGEBRA-II in this site

    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".

Save the link to this textbook together with its description Free of charge online textbook in ALGEBRA-II https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson into your archive and use when it is needed.

7. Six couples want to have their pictures taken. In how many ways can they arrange themselves in a row i couples must stay together?
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A. 8. How many five-digit numbers can be formed from the numbers , , , , , and if repetition of digits is allowed? A C n z9

Six couples want to have their picture taken in how many ways can they arrange themselves in a row

Given: n = r = 6 couples = 12 people

Formula: P(n,r) = n!/(n-r)!

Solution:

P(12,12) = 12!/(12-12)!

P(12,12) = 12!

P(12,12) = 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 479,001,600 ways