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enter image description here I know that $H(x) = -\sum(p(x_i)\log(p(x_i))$ And I have found $P(x_i)=1/6\cdot(5/6)^{i-1}$ However I do not know how to calculate this when I put $P(x_i)$ into the formula $H(x)$ $\endgroup$ 2
Asked by HighnessGrouseMaster444 Image transcription text Let X be a random variable denoting the outcomes of a fair dice. What is the min-entropy of X? Answer: 6 X ... Show more
Answer & Explanation Solved by verified expert Answered by saieshdurga37
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