In how many ways a four digit even number can be formed by using the digits 4, 5,9 8 exactly once

Permutation Combination Questions: Solved 27 Permutation Combination Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Category online test. Category Questions section with detailed description, explanation will help you to master the topic.

1. An intelligence agency forms a code of two distinct digits selected from 0, 1, 2, …., 9 such that the first digit of the code is nonzero. The code, handwritten on a slip, can however potentially create confusion, when read upside down-for example, the code 91 may appear as 16. How many codes are there for which no such confusion can arise? 


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Correct Ans:71

Explanation:

The available digits are 0,1,2, …9. The first digit can be chosen in 9 ways (0 not acceptable), the second digit can be accepted in 9 ways (digits repetition not allowed). Thus, the code can be made in 9 × 9 = 81 ways. Now there are only 4 digits 1, 6, 8, 9 which can create confusion. Hence, the total number of codes which create confusion are = 4 × 3 = 12. Out of these 12 codes 69 and 96 will not create confusion. Hence, in total 12 – 2 = 10 codes will create confusion.

Hence, the total codes without confusion are 81 – 10 = 71.


2. If a refrigerator contains 12 cans such that 7 blue cans and 5 red cans. In how many ways can we remove 8 cans so that at least 1 blue can and 1 red can remains in the refrigerator. 


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Correct Ans:455

Explanation:

Given

Total No of Cans = 12

Total No of Red Cans = 7

Total No of Blue Cans = 5

Given Condition - No of Possible ways to draw 8 balls from the refrigerator which contains at least 1 blue and 1 red can

No of Possible ways are => (6,2) (5,3) (4,4) => 7 C 6 * 5 C2 => 7 * 10 => 70 => 7C5 * 5 C3 => 7 * 3 * 5 * 2 => 21 * 10 => 210 => 7C4 * 5C4 => 35 * 5 => 175 Total Ways = 70 +210 + 175

=> 455.


3. There is meeting of 20 delegates that is to be held in a hotel. In how many ways these delegates can be seated along a round table, if three particular delegates always seat together?


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Correct Ans:17! 3!

Explanation:

Give Total 20 persons, 3 always seat together, 17 + 1 =18 delegates can be seated in (18 -1)! Ways = 17! And now that three can be arranged in 3! Ways.

So, 17! 3! is the correct answer.


4. In how many ways a four digit even number can be formed by using the digits 2,3,5,8 exactly once?


SHOW ANSWER

Correct Ans:12

Explanation:

Solution is
Given
Four digit even number can be formed by using the digits 2,3,5,8 Since the number has to be an even number,the unit digit has to be 2 or 8. First three places can be filled by remaining three digits.

In how many ways a four digit even number can be formed by using the digits 4, 5,9 8 exactly once

= 3! + 3!

&nb


5. In a plane there are totally 8 points (no three points are collinear), how many lines can be drawn ?


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Correct Ans:28

Explanation:

To draw a line we need 2 points. From the given 8 points , we need to choose 2 points Number of ways in which this can be done is 18C2= (8 x 7 ) / 2 = 28


6. How many 4 digit even number can formed by using the digits 1,3,7 and 8 only once ?


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Correct Ans:6

Explanation:

We can form 24 numbers with digits 1,3,7 and 8 using only once. To be an even number, the units digit has to even number, in this case only 8 should come in the unit's place . The remaining places, 3 positions can be filled in 3! , that is 6 ways


7. How many words can be formed with or without meaning by taking all the letters from the word TAKEN ?


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Correct Ans:120

Explanation:

There are totally 4 letters in the word TAKEN T, A, K, E and N. No. Of Words = 5 x 4 x 3 x 2 x 1 = 120


8. In how many different ways can the letters of the word 'OFFICES' be arranged ?


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Correct Ans:2520

Explanation:

The word OFFICES contains O,F, F I, C, E, S contains 7 letters, in which 2 are identical. No. Of words that can formed = 7 ! / 2 ! = 2520



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Correct Ans:600

Explanation:

25! / 23! = 23! X 24 x 25 / ( 23!) = 24 x 25 = 600


10. In a party there were totally 20 people, each person shook his hands with the other person. How many hand shakes would have taken place ?


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Correct Ans:190

Explanation:

There are 20 people. Every person has to shake hands with the other person. Which means we have to find the number of ways of choosing 2 people from the 20. The number of ways it ca happen = 20C2 = ( 20 x 19 ) / (1 x 2) = 190


11. A letter lock consists of 4 rings, each ring contains 9 non-zero digits. This lock can be opened by setting a 4 digit code with the proper combination of each of the 4 rings Maximum how many codes can be formed to open the lock?


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Correct Ans:9 x 9 x 9 x 9

Explanation:

9 x 9 x 9 x 9 = 94


12. How many words can be formed with or without meaning by taking all the letters from the word SMALL ?


SHOW ANSWER

Correct Ans:60

Explanation:

Number of letters in SMALL is 5, but there are 2 L?s Answer is 5! / 2! = 120 / 2 = 60


13. In how many different ways can the letters of the word 'OPTICAL' be arranged so that the vowels always come together?


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Correct Ans:720

Explanation:

The word 'OPTICAL' contains 7 different letters. When the vowels OIA are always together, they can be supposed to form one letter. Then, we have to arrange the letters PTCL (OIA). Now, 5 letters can be arranged in 5! = 120 ways. The vowels (OIA) can be arranged among themselves in 3! = 6 ways. Required number of ways = (120 x 6)

= 720.


14. How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?


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Correct Ans:5040

Explanation:

LOGARITHMS' contains 10 different letters. Required number of words = Number of arrangements of 10 letters, taking 4 at a time.

= 10P4 = (10 x 9 x 8 x 7) = 5040.


15. In how many different ways can the letters of the word 'DETAIL' be arranged in such a way that the vowels occupy only the odd positions?


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Correct Ans:36

Explanation:

There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants. Let us mark these positions as under: (1) (2) (3) (4) (5) (6) Now, 3 vowels can be placed at any of the three places out 4, marked 1, 3, 5. Number of ways of arranging the vowels = 3P3 = 3! = 6. Also, the 3 consonants can be arranged at the remaining 3 positions. Number of ways of these arrangements = 3P3 = 3! = 6. Total number of ways = (6 x 6) = 36.


16. In how many ways can the letters of the word 'LEADER' be arranged ?


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Correct Ans:360

Explanation:

The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.
Therefore, Required number of ways = 6! / (1!)(2!)(1!)(1!)(1!) = 360


17. How many numbers greater than a million can be formed by using the digits 7, 4, 6 and 0 if 4 has to be used twice, 6 has to be used thrice and the rest only once?


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Correct Ans:360

Explanation:

The given digits are 4, 4, 6, 6, 6, 7 and 0. Totally we have 7 digits. So numbers greater than a million can be formed by using all the digits. 4 occurs twice, 6 occurs thrice while 0 and 7 once, Therefore total number of arrangements = 7! / (3! x 2!) = 420 We have to avoid 0 in the starting place, Number of ways in which 0 can be in the first place is 6! / 2! X 3! = 60 Hence the total number of ways = 420 – 60 = 360


18. In how many ways a four digit even number can be formed by using the digits 4,5,9,8 exactly once.


SHOW ANSWER

Correct Ans:12

Explanation:

Given Four digit even number can be formed by using the digits 4,5,9,8 Since the number has to be a even digit number,the units digit has to be 4 or 8. First three places can be filled by remaining three digits. Hence it is totally 6 x 2 = 12 ways

Answer is 12


19. In how many ways a four digit even number can be formed by using the digits 2,3,5,8 exactly once?


SHOW ANSWER

Correct Ans:12

Explanation:

Solution is
Given
Four digit even number can be formed by using the digits 2,3,5,8 Since the number has to be an even number,the unit digit has to be 2 or 8. First three places can be filled by remaining three digits.

In how many ways a four digit even number can be formed by using the digits 4, 5,9 8 exactly once

= 3! + 3! = (3*2*1)+(3*2*1) = 6 + 6 =12

Hence totally 12 ways


20. In a plane there are totally 8 points (no three points are collinear), how many lines can be drawn ?


SHOW ANSWER

Correct Ans:28

Explanation:

To draw a line we need 2 points. From the given 8 points , we need to choose 2 points Number of ways in which this can be done is 18C2= (8 x 7 ) / 2 = 28


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This page provides important questions on Permutation Combination along with correct answers and clear explanation, which will be very useful for various Interviews, Competitive examinations and Entrance tests. Here, Most of the Permutation Combination questions are framed with Latest concepts, so that you may get updated through these Permutation Combination Online tests. Permutation Combination Online Test questions are granted from basic level to complex level.

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Winners are those who can use the simplest method for solving a question. So that they have enough time for solving all the questions in examination, correctly without any tense. Fresherslive provides most simplest methods to answer any tough questions. Practise through Fresherslive test series to ensure success in all competitive exams, entrance exams and placement tests.

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Permutation Combination Questions: Solved 27 Permutation Combination Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Category online test. Category Questions section with detailed description, explanation will help you to master the topic.

21. How many 4 digit even number can formed by using the digits 1,3,7 and 8 only once ?


SHOW ANSWER

Correct Ans:6

Explanation:

We can form 24 numbers with digits 1,3,7 and 8 using only once. To be an even number, the units digit has to even number, in this case only 8 should come in the unit's place . The remaining places, 3 positions can be filled in 3! , that is 6 ways


22. How many words can be formed with or without meaning by taking all the letters from the word TAKEN ?


SHOW ANSWER

Correct Ans:120

Explanation:

There are totally 4 letters in the word TAKEN T, A, K, E and N. No. Of Words = 5 x 4 x 3 x 2 x 1 = 120


23. In how many different ways can the letters of the word 'OFFICES' be arranged ?


SHOW ANSWER

Correct Ans:2520

Explanation:

The word OFFICES contains O,F, F I, C, E, S contains 7 letters, in which 2 are identical. No. Of words that can formed = 7 ! / 2 ! = 2520



SHOW ANSWER

Correct Ans:600

Explanation:

25! / 23! = 23! X 24 x 25 / ( 23!) = 24 x 25 = 600


25. In a party there were totally 20 people, each person shook his hands with the other person. How many hand shakes would have taken place ?


SHOW ANSWER

Correct Ans:190

Explanation:

There are 20 people. Every person has to shake hands with the other person. Which means we have to find the number of ways of choosing 2 people from the 20. The number of ways it ca happen = 20C2 = ( 20 x 19 ) / (1 x 2) = 190


26. A letter lock consists of 4 rings, each ring contains 9 non-zero digits. This lock can be opened by setting a 4 digit code with the proper combination of each of the 4 rings Maximum how many codes can be formed to open the lock?


SHOW ANSWER

Correct Ans:9 x 9 x 9 x 9

Explanation:

9 x 9 x 9 x 9 = 94


27. How many words can be formed with or without meaning by taking all the letters from the word SMALL ?


SHOW ANSWER

Correct Ans:60

Explanation:

Number of letters in SMALL is 5, but there are 2 L?s Answer is 5! / 2! = 120 / 2 = 60


Are you seeking for good platform for practicing Permutation Combination questions in online. This is the right place. The time you spent in Fresherslive will be the most beneficial one for you.

This page provides important questions on Permutation Combination along with correct answers and clear explanation, which will be very useful for various Interviews, Competitive examinations and Entrance tests. Here, Most of the Permutation Combination questions are framed with Latest concepts, so that you may get updated through these Permutation Combination Online tests. Permutation Combination Online Test questions are granted from basic level to complex level.

Permutation Combination questions are delivered with accurate answer. For solving each and every question, very lucid explanations are provided with diagrams wherever necessary.

Practice in advance of similar questions on Permutation Combination may improve your performance in the real Exams and Interview.

Time Management for answering the Permutation Combination questions quickly is foremost important for success in Competitive Exams and Placement Interviews.

Through Fresherslive Permutation Combination questions and answers, you can acquire all the essential idea to solve any difficult questions on Permutation Combination in short time and also in short cut method.

Winners are those who can use the simplest method for solving a question. So that they have enough time for solving all the questions in examination, correctly without any tense. Fresherslive provides most simplest methods to answer any tough questions. Practise through Fresherslive test series to ensure success in all competitive exams, entrance exams and placement tests.

Most of the job seekers finding it hard to clear Permutation Combination test or get stuck on any particular question, our Permutation Combination test sections will help you to success in Exams as well as Interviews. To acquire clear understanding of Permutation Combination, exercise these advanced Permutation Combination questions with answers.

You're Welcome to use the Fresherslive Online Test at any time you want. Start your beginning, of anything you want by using our sample Permutation Combination Online Test and create yourself a successful one. Fresherslive provides you a new opportunity to improve yourself. Take it and make use of it to the fullest. GOODLUCK for Your Bright Future.