How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?

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How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?

How many 4-digit numbers can be formed from the digits 2, 3, 5, 6, 7 [#permalink]

How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
  27 Sep 2021, 18:36

How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?

How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?

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How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
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How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
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How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
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How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
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How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?

kapil1995 wrote:

How many 4-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

a) 30 b) 40 c) 60 d) 20 e) None of these

For a number to be divisible by 5, it should end in 0 or 5.Thus the number will be ABC5.A, B and C can be chosen from remaining 5 numbers in 5*4*3 or 60 ways.

C

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Re: How many 4-digit numbers can be formed from the digits 2, 3, 5, 6, 7 [#permalink]

How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
  27 Sep 2021, 21:19

Divisibility rule of 5: A number is divisible by 5 if the unit digit is 5 or 0Let the number be XYZWUnit place or W has only 1 choice(that is 5)Place Z has 5 choices (2,36,7,9)Place Y has 4 choices (as digits are not repeated)Place X has 3 choices(as digits are not repeated)By Fundamental Principle of Counting,total number of numbers= 1 * 5*4*3 = 60 numbers

(option c)

D.S
GMAT SME

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How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?

Joined: 16 Jun 2021

Posts: 1072

Re: How many 4-digit numbers can be formed from the digits 2, 3, 5, 6, 7 [#permalink]

How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?
  27 Sep 2021, 23:03

kapil1995 wrote:

How many 4-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

a) 30 b) 40 c) 60 d) 20 e) None of these

For a number to be divisible by 5 it should be having 5 or 0 at the end Therefore number of possibilities for number 5 fixed at the end and non repeating = 5*4*3*1 = 60

Therefore IMO C

How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?

Re: How many 4-digit numbers can be formed from the digits 2, 3, 5, 6, 7 [#permalink]

$\begingroup$

How many 4 digits numbers divisible by 5 can be formed with digits 0,1,2,3,4,5,6 and 6

options:

a) $220$ b) $249$ c) $432$ d) $216$

MyApproach:

To form a 4 digit number divisible by 5 using given numbers

I make cases here:

Unit Digit is $0$ and other $3$ numbers can be formed in $7$ . $6$ . $5$=$210$

Unit Digit is $5$ and other $3$ numbers can be formed in $6$ . $6$ . $5$=$180$

Therefore,the required number is $390$

Is my approach right?Please correct me if I am wrong?

$\endgroup$

0

How many 4 digit numbers can be formed from the digits 1,2 3 4 5 6 7 which are divisible by 5 when none of the digits is repeated?

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120 Questions 480 Marks 120 Mins

Given:
Digits = 2, 3, 5, 6, 7 and 9

Concept used: Divisibility rule of 5:

The number is divided by 5, if the unit digit of a number is either 5 or 0.

Calculation: Unit digit can only be 5. There is only 1 possible way to fill unit place. Remaining places can be filled by 2, 3, 6, 7 or 9. There is 5 possible ways to fill ten's place. There is 4 possible ways to fill hundredth place as digits cannot be repeated. There is 3 possible ways to fill the first place of four digit number.  Total numbers that can be formed = 1 × 5 × 4 × 3 = 60

∴ 60 four-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9.

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