How many 4 digit even numbers greater than 5000 can you form using the digits 0 1 2 3 5 6 8 and 9 without repetitions?

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You are to create $3$ digit even numbers greater than $400$ so think as follows:

It cannot start with a number less than $4$. So let us start with $4$, then you only have one choice left for the last digit, namely $2$. Can you figure out the rest? (you can peek by mouseovering the yellow boxes, but try to figure out yourself first, before you peek)

$3$ different numbers since the first and last digit is determined and you have $3$ other digits to choose from to fill the middle

It can also start with a $5$, in this case it can end with both $2$ and a $4$. I am sure you can figure the rest out ;)

If it ends with a $2$ you have $3$ choices for the middle number, since once again we fixed the first and the last digit and the same is true for when it ends with a $4$

Adding these together you end up with

a total number of $3+3+3=9$ possibilities.

Hope I could help