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how long would it take for a ball dropped from the top of a 144 foot building to hit the ground
As an object falls, its speed increases because it’s being pulled on by gravity.
The acceleration of gravity near the earth is g = 32.2 feet/sec^2.
The formula for T = time of the fall is
T = (2d/g)^0.5
where d = 1440 foot and g = 32.2 feet/sec^2
T = (2*1440/32.2)^0.5
T = 9.457 sec approximately.
The ball will hit the ground in approximately 9.457 seconds.
You can put this solution on YOUR website!
ft
This just says that at ,
the ball is ft above ground ------------ I need to find when the ball is at the
ground, or when
sec
Kim O.
1 Expert Answer
To solve this problem you need the function
v0 is the initial velocity, which in our case is 0
h0 = initial height, which in our case is 256
h(t) = 0 since we want to know when the ball will hit the ground.
If we rearrange the terms we see that this is a difference of 2 squares
The second solution is discarded as time cannot be negative.
So the ball will hit the ground in 4 seconds.
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How long would it take for a ball dropped from the top of a 100 100 -foot building to hit the ground? Round your answer to two decimal places.