how long would it take for a ball dropped from the top of a 144 foot building to hit the ground As an object falls, its speed increases because it’s being pulled on by gravity. The acceleration of gravity near the earth is g = 32.2 feet/sec^2. The formula for T = time of the fall is T = (2d/g)^0.5 where d = 1440 foot and g = 32.2 feet/sec^2 T = (2*1440/32.2)^0.5 T = 9.457 sec approximately. The ball will hit the ground in approximately 9.457 seconds.
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ft This just says that at , the ball is ft above ground ------------ I need to find when the ball is at the ground, or when sec Kim O. 1 Expert Answer To solve this problem you need the function v0 is the initial velocity, which in our case is 0 h0 = initial height, which in our case is 256 h(t) = 0 since we want to know when the ball will hit the ground. If we rearrange the terms we see that this is a difference of 2 squares The second solution is discarded as time cannot be negative. So the ball will hit the ground in 4 seconds.
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How long would it take for a ball dropped from the top of a 100 100 -foot building to hit the ground? Round your answer to two decimal places. |