How long would it take a ball dropped from the top of a 484 foot building to hit the ground?

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how long would it take for a ball dropped from the top of a 144 foot building to hit the ground

As an object falls, its speed increases because it’s being pulled on by gravity.

The acceleration of gravity near the earth is g = 32.2 feet/sec^2.

The formula for T = time of the fall is

T = (2d/g)^0.5

where d = 1440 foot and g = 32.2 feet/sec^2

T = (2*1440/32.2)^0.5

T = 9.457 sec approximately.

The ball will hit the ground in approximately 9.457 seconds.

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How long would it take a ball dropped from the top of a 484 foot building to hit the ground?
Note that:

How long would it take a ball dropped from the top of a 484 foot building to hit the ground?


ft
This just says that at ,
the ball is ft above ground ------------ I need to find when the ball is at the

ground, or when

How long would it take a ball dropped from the top of a 484 foot building to hit the ground?







sec

Kim O.

asked • 02/09/16

1 Expert Answer

To solve this problem you need the function

v0 is the initial velocity, which in our case is 0

h0 = initial height, which in our case is 256

h(t) = 0 since we want to know when the ball will hit the ground.

If we rearrange the terms we see that this is a difference of 2 squares

The second solution is discarded as time cannot be negative.

So the ball will hit the ground in 4 seconds.

How long would it take a ball dropped from the top of a 484 foot building to hit the ground?

How long would it take a ball dropped from the top of a 484 foot building to hit the ground?
How long would it take a ball dropped from the top of a 484 foot building to hit the ground?

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