Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan. Buy NowComplete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan. Buy Now- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan. Buy Now- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan. Buy Now- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan. Buy NowPage 2
Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan. Buy NowComplete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan. - AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan. Buy Now- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan. Buy Now- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan. Buy NowText Solution Solution : In hydrogen spectrum the spectral lines are expressed are expressed in term of wave number `vecv` obey the following formula ltbr. Wave number `vecv=R_(H)((1)/( n_(i)^(2))-(1)/(n_(f)^(2)))` (where `R_(H)=` Rydberg constant `109677cm^(-1)`) <br> `vecv=109677cm^(-1)((1)/(2^(2))-(1)/(3^(2)))` <br> `vecv=109677xx(5)/(36)=15232g cm^(-1)` <br> `vecv=(1)/(lambda)` <br> or `lambda=(1)/(v)=(1)/(15232g)=6.564xx10^(-5)cm` <br> Wavelength, `lambda=6.564xx10^(-7)m` ltbr. Energy `E=(hc)/(lambda)` <br> `=(6.626xx10^(-34)Jsxx30xx10^(8)ms^(-1))/(6.564xx10^(-7)m)` <br> `=3.028xx10^(-19)J` <br> Frequency `v=(c)/(lambda)=(c)/(lambda)=(3.0xx10^(8)ms^(-1))/(6.564xx10^(-7)m)` <br> `=0.457xx10^(15)s^(-1)=4.57xx10^(14)s^(-1)` Open in App Suggest Corrections 0 |