A die thrown once. Find the probability of getting(i) an even prime number (ii) a multiple of 3
If a die thrown once then possible outcomes areS = {1, 2, 3, 4, 5, 6} i.e. n(S) = 6(i) Let A be the favourable outcomes of getting an even prime number, thenA = [2] i.e. n(A) = 2 Therefore, P(A) = (ii) Let B be the favourable outcomes of getting a multiple of three, thenB = {3,6} i.e. n(B) = 2 Therefore, P(B) = Open in App Suggest Corrections 8 |